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Differential Calculus: From Basics to Advanced | bAstronautWay

Advanced Mathematics

Table of Contents

Differential
Calculus

Master partial differentiation, chain rule, total derivatives, Euler’s theorem, Jacobians and functional dependence through concepts, derivations and worked mathematical examples.

Presented by Grandmaster Bikram Sutradhar
bAstronautWay

Complete Syllabus

  • ✓ Partial Differentiation
  • ✓ Chain Rule
  • ✓ Change of Variables
  • ✓ Total Derivative
  • ✓ Mixed Partial Derivatives
  • ✓ Euler’s Theorem
  • ✓ Converse of Euler’s Theorem
  • ✓ Jacobian
  • ✓ Functional Dependence
  • ✓ MCQ Examination
Learning Roadmap

What You Will Learn

01

Partial Differentiation

Differentiate multivariable functions while keeping other variables constant.

02

Chain Rule

Differentiate composite functions involving several dependent variables.

03

Change of Variables

Transform derivatives when variables are replaced by new coordinates.

04

Total Derivative

Understand how all changing variables contribute to a differential.

05

Mixed Partials

Understand conditions under which mixed partial derivatives are equal.

06

Euler’s Theorem

Use homogeneity to obtain powerful differential identities.

07

Jacobian

Study determinant-based transformation of multivariable variables.

08

Functional Dependence

Determine whether several functions are independently variable.

1. Partial Differentiation

Suppose a function depends on two or more independent variables:

z = f(x,y)
The partial derivative with respect to x means that y is treated as constant.
∂z/∂x = fₓ
Similarly, while differentiating with respect to y, x is kept constant:
∂z/∂y = fᵧ

Example 1

z = x³y² + 4xy + y³
With respect to x:
∂z/∂x = 3x²y² + 4y
With respect to y:
∂z/∂y = 2x³y + 4x + 3y²
Golden Rule: For ∂/∂x, treat every other independent variable as a constant.

Second Partial Derivatives

fₓₓ = ∂²f/∂x²

fᵧᵧ = ∂²f/∂y²

fₓᵧ = ∂/∂y(∂f/∂x)

fᵧₓ = ∂/∂x(∂f/∂y)

2. Chain Rule for Partial Derivatives

The chain rule is used when a variable depends indirectly on other variables.

Suppose
z=f(x,y)
and
x=x(t),   y=y(t)
Then
dz/dt = (∂z/∂x)(dx/dt) + (∂z/∂y)(dy/dt)

Example

z=x²+y²
where
x=t²,   y=3t
First:
∂z/∂x=2x
∂z/∂y=2y
Also:
dx/dt=2t
dy/dt=3
Therefore:
dz/dt = 2x(2t)+2y(3)
Substitute x=t² and y=3t:
dz/dt = 4t³+18t

3. Change of Variables

Suppose x and y are functions of u and v:

x=x(u,v)
y=y(u,v)
and
z=f(x,y)
Then:
∂z/∂u = (∂z/∂x)(∂x/∂u) + (∂z/∂y)(∂y/∂u)
Similarly:
∂z/∂v = (∂z/∂x)(∂x/∂v) + (∂z/∂y)(∂y/∂v)

Example

Let
z=x²+y²
and
x=u+v
y=u−v
Then
z=(u+v)²+(u−v)²
Therefore
z=2u²+2v²
Hence
∂z/∂u=4u
∂z/∂v=4v
Changing variables is especially important in polar, cylindrical, spherical and other coordinate transformations.

4. Total Derivative

If z depends on x and y and both x and y depend on another variable, then the change in z contains contributions from both x and y.

If
z=f(x,y)
then the total differential is
dz = (∂z/∂x)dx + (∂z/∂y)dy
If x=x(t) and y=y(t):
dz/dt = (∂z/∂x)(dx/dt) + (∂z/∂y)(dy/dt)

Three Variables

If
u=f(x,y,z)
then
du = uₓ dx + uᵧ dy + u_z dz
If x,y,z depend on t:
du/dt = uₓ dx/dt + uᵧ dy/dt + u_z dz/dt
Do not confuse:
Partial derivative = vary one independent variable while keeping others fixed.

Total derivative = account for all variables that are changing.

5. Equality of Mixed Partial Derivatives

For a sufficiently smooth function, under the usual continuity conditions on the relevant second partial derivatives:

∂²f/∂x∂y = ∂²f/∂y∂x
This is commonly associated with Clairaut’s theorem (or Schwarz’s theorem).

Example

f=x³y²+4xy
First differentiate with respect to x:
fₓ=3x²y²+4y
Now y:
fₓᵧ=6x²y+4
Reverse order:
fᵧ=2x³y+4x
Then x:
fᵧₓ=6x²y+4
Therefore:
fₓᵧ=fᵧₓ
Exam shortcut: For polynomial functions, mixed partials are normally straightforward to calculate and will agree.

6. Homogeneous Functions of Two Variables

A function f(x,y) is homogeneous of degree n if:

f(λx,λy)=λⁿf(x,y)
for a suitable scaling parameter λ.

Example

f(x,y)=x³+2x²y+xy²
Every term has total degree 3.Therefore f is homogeneous of degree 3.
f(λx,λy) = λ³f(x,y)

7. Euler’s Theorem for Homogeneous Functions

If f(x,y) is homogeneous of degree n, then:

x(∂f/∂x)+y(∂f/∂y)=nf
This is one of the most important formulas in this chapter.

Proof

Since f is homogeneous of degree n:
f(tx,ty)=tⁿf(x,y)
Differentiate both sides with respect to t:
fₓ(tx,ty)x + fᵧ(tx,ty)y = ntⁿ⁻¹f(x,y)
Put t=1:
xfₓ+yfᵧ=nf
Hence proved.

Example

f=x³+2x²y+xy²
Degree:
n=3
Compute:
fₓ=3x²+4xy+y²
fᵧ=2x²+2xy
Therefore:
xfₓ+yfᵧ = 3x³+6x²y+3xy²
which is
3f
Thus Euler’s theorem is verified.

8. Euler’s Theorem for Three Variables

If

u=f(x,y,z)
is homogeneous of degree n, then:
x uₓ + y uᵧ + z u_z = nu

Example

u=x²y+y²z+z²x
Each term has degree 3.Therefore n=3.Euler’s theorem gives:
xuₓ+yuᵧ+zu_z=3u
Memory Formula:

2 variables → x fₓ + y fᵧ = nf

3 variables → x fₓ + y fᵧ + z f_z = nf

9. Second-Order Euler Relation

If f(x,y) is homogeneous of degree n, differentiating Euler’s identity gives a useful second-order relation:

x²fₓₓ + 2xyfₓᵧ + y²fᵧᵧ = n(n−1)f
For three variables:
x²uₓₓ+y²uᵧᵧ+z²uzz +2xyuₓᵧ +2yzuᵧz +2zxu_zₓ = n(n−1)u
This second-order form is extremely useful in higher-level exam problems involving homogeneous functions.

10. Converse of Euler’s Theorem

Under appropriate differentiability assumptions, if a differentiable function satisfies

xfₓ+yfᵧ=nf
throughout a suitable domain, then f behaves as a homogeneous function of degree n.In other words, Euler’s differential identity can be used as a test for homogeneity.

Example

Suppose
f=x²+y²
Then
fₓ=2x
fᵧ=2y
Hence
xfₓ+yfᵧ = 2x²+2y² = 2f
Therefore f is homogeneous of degree 2.
Exam Strategy: If you are given a differential equation of the form xfₓ+yfᵧ=nf, immediately suspect homogeneity of degree n.

11. Jacobian

The Jacobian describes how a transformation between variables changes locally.

For
u=u(x,y)
v=v(x,y)
the Jacobian is
∂(u,v)/∂(x,y) = | uₓ uᵧ | | vₓ vᵧ |
Therefore:
∂(u,v)/∂(x,y) = uₓvᵧ-uᵧvₓ

Example

Let
u=x+y
v=x−y
Then
uₓ=1, uᵧ=1
vₓ=1, vᵧ=−1
Hence
J = (1)(−1)−(1)(1) = −2
Therefore:
∂(u,v)/∂(x,y)=−2

12. Reciprocal Property of Jacobians

When the transformation is locally invertible and the required derivatives exist:

∂(u,v)/∂(x,y) × ∂(x,y)/∂(u,v) = 1
Therefore:
∂(x,y)/∂(u,v) = 1 / [∂(u,v)/∂(x,y)]
provided the Jacobian is non-zero.
If the Jacobian is zero, the simple reciprocal formula cannot be used at that point as an ordinary local inverse formula.

13. Functional Dependence

Functions u and v are functionally dependent if there exists a non-trivial relation:

F(u,v)=0
between them.For two functions of two variables, a standard test is:
∂(u,v)/∂(x,y)=0
If the Jacobian vanishes identically in the relevant region, the functions are functionally dependent under the usual regularity assumptions.

Example

Let
u=x+y
v=(x+y)²
Clearly:
v=u²
Therefore:
v−u²=0
So u and v are functionally dependent.Check the Jacobian:
uₓ=1, uᵧ=1
vₓ=2(x+y), vᵧ=2(x+y)
Therefore:
J = 1·2(x+y) − 1·2(x+y) = 0
Hence the Jacobian test confirms the dependence.

⚡ Master Formula Sheet

ConceptFormula
Partial derivativefₓ = ∂f/∂x
Total differentialdz=fₓdx+fᵧdy
Chain ruledz/dt=fₓ dx/dt+fᵧ dy/dt
Mixed partialsfₓᵧ=fᵧₓ under suitable regularity conditions
Homogeneityf(λx,λy)=λⁿf(x,y)
Euler: 2 variablesxfₓ+yfᵧ=nf
Euler: 3 variablesxfₓ+yfᵧ+zf_z=nf
Second Euler relationx²fₓₓ+2xyfₓᵧ+y²fᵧᵧ=n(n−1)f
Jacobian∂(u,v)/∂(x,y)=uₓvᵧ−uᵧvₓ
Reciprocal Jacobian∂(u,v)/∂(x,y) · ∂(x,y)/∂(u,v)=1
Functional dependenceJ=0 under appropriate conditions
Online Examination

Differential Calculus MCQ Test

15 questions • Instant result • Concept-based assessment

1. In ∂f/∂x, which variable is kept constant for f(x,y)?

2. If z=f(x,y), x=x(t), y=y(t), then dz/dt equals:

3. A homogeneous function of degree n satisfies:

4. Euler’s theorem for f(x,y) homogeneous of degree n is:

5. For a homogeneous function of three variables of degree n:

6. The Jacobian ∂(u,v)/∂(x,y) is:

7. If u=x+y and v=x−y, the Jacobian is:

8. Under suitable conditions, mixed partial derivatives satisfy:

9. The total differential of z=f(x,y) is:

10. x²+y² is homogeneous of degree:

11. If J=∂(u,v)/∂(x,y) ≠ 0, the transformation is locally:

12. If J=0 identically, the usual Jacobian criterion suggests:

13. For f=x³+2x²y+xy², its degree of homogeneity is:

14. For a homogeneous function of degree n, the second Euler relation is:

15. If u=x+y and v=(x+y)², then u and v are:

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Differential Calculus: Complete Notes, Formulas, Examples & MCQ Test | bAstronautWay

  1. Differential Calculus Master Guide | Partial Derivatives, Euler’s Theorem, Jacobian & MCQs
  2. Differential Calculus Complete Course | Concepts, Derivations, Examples & Practice Test
  3. Advanced Differential Calculus | Partial Differentiation, Jacobians & Euler’s Theorem

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